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-3x^2-0.75x+1.5=0
a = -3; b = -0.75; c = +1.5;
Δ = b2-4ac
Δ = -0.752-4·(-3)·1.5
Δ = 18.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.75)-\sqrt{18.5625}}{2*-3}=\frac{0.75-\sqrt{18.5625}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.75)+\sqrt{18.5625}}{2*-3}=\frac{0.75+\sqrt{18.5625}}{-6} $
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